Hi there, I'm sure the answer to this is incredibly obvious, but something is slipping my mind:
│x-3│= x + 2
if you move the x out of the absolute value braket, the x's cancel... so how do you solve it?
You can see that the two sides are going to have alternative signs, meaning either (x-3) will be negative or (x+2) will be negative so cancel the absolute value, and make either side negative:
Distribute the negative sign
Subtract (x+3) from both sides
Distribute the negatives
Divide both sides by -2