Hi;
I'm trying to determine if the equation h = -16t^2 + vt + s works out like this where

-16t^2 is the amount of speed a free falling object falls through the air ie for the first second it falls
16 feet then for the second its speed is doubled then triple for the third second and so on?

vt starting velocity

s is the starting height of the object.

and all this is without the consideration of wind speed, weight of object ect...

Thanks.

Originally Posted by anthonye
Hi;
I'm trying to determine if the equation h = -16t^2 + vt + s works out like this where

-16t^2 is the amount of speed a free falling object falls through the air ie for the first second it falls
16 feet then for the second its speed is doubled then triple for the third second and so on?

vt starting velocity

s is the starting height of the object.

and all this is without the consideration of wind speed, weight of object ect...

Thanks.
I am not clear what your question is! "works out like" what?

No, "-16t^2" is NOT "the amount of speed a free falling object falls through the air", it is the (approximate since the "16" is only approximate) distance an object with no initial speed would fall in t seconds.

No, "vt" is NOT "starting velocity". "v" is the starting velocity. "vt" is the distance an object with starting velocity v, and no acceleration, would fall in t seconds. It is this term that gives "for the first second it falls 16 feet then for the second its speed is doubled then triple for the third second and so on", not the "-16t^2".

Yes, s is the starting height of the object.

Since "h" is a distance, all three terms, "-16t^2", "vt", and "h" are distances.

All this is "without the consideration of wind speed", or even air resistance in still air, i.e. "in vacuum", but it is NOT "without consideration of weight of object". All objects of any weight fall the same in vacuum.

(And "et cetera" is abbreviated "etc.", not "ect.". That's a pet peeve of mine!)