g(x)<0, when x=/ -2 How do I calculate and what is the answer? ( it is a graph)
I assume that this notation means that, If $x\ne -2$ then $g(x)<0$. However it does not tell what $g(-2)=~?$.
In other words, is $g$ a function from all real numbers? Or is it just a relation or some sort.
I think that you ought post the exact wording of the given question.
So you are to graph the inequality, g(x)< 0? Assuming that g(x) is a continuous function then the points where g(x)= 0 separates those where g(x)< 0 from g(x)> 0. So the first step should be to find all x such that g(x)= 0. Of course that depends strongly upon what g(x) is! And you haven't told us that. Quite often when we talk about a "graph" we are thinking of a graph of "y= f(x)" in two dimensions (an xy-coordinate system), but just "g(x)< 0", without a "y", would be on a single "number line". Again, on a number line, mark those values of x such that g(x)= 0. Choose one point in each interval between those points to see whether it satisfies g(x)> 0 or g(x)< 0.
Of course, in all of this I am having to guess what properties g(x) has and what the question really is.