For what integral values of n is the expression (*-means to the)))
( 1*n+ 2*n +3*n +4*n ) divisible by 5
thanks so much for the help
i think it must be a multiple by three but i dont know how to prove it
For what integral values of n is the expression (*-means to the)))
( 1*n+ 2*n +3*n +4*n ) divisible by 5
thanks so much for the help
i think it must be a multiple by three but i dont know how to prove it
I'm not sure I understand your post.
Is this what you mean?
For what value of $\displaystyle n$ is this expression divisible by $\displaystyle 5$?
$\displaystyle 1^n + 2^n + 3^n + 4^n$
Note that $\displaystyle 1 + 2 + 3 + 4 = 10$, which is divisible by $\displaystyle 5$.
So, for what value of n are $\displaystyle 1^n$, $\displaystyle 2^n$, $\displaystyle 3^n$, and $\displaystyle 4^n$ equal to $\displaystyle 1$, $\displaystyle 2$, $\displaystyle 3$ and $\displaystyle 4$, respectively?
The answer to this is of course $\displaystyle 1$. If you take anything to the power of $\displaystyle 1$, it will be equal to itself.
If you need to find all values of $\displaystyle n$ for which this expression is divisible by $\displaystyle 5$, note that every odd integer $\displaystyle n$ gives a number that is divisible by $\displaystyle 5$.