Results 1 to 3 of 3

Thread: Calculate a third mixture from blending two different mixtures

  1. #1
    Newbie
    Joined
    Dec 2017
    From
    earth
    Posts
    1

    Calculate a third mixture from blending two different mixtures

    Here's the question:

    I have an unlimited supply of 1% mixture of salt and water (Mixture #1)

    I have 2.5kg of a 10% mixture of salt and water (Mixture #2)

    How much of Mixture #1 do I need to add to Mixture #2 in order to make a 3.33% 9000mL solution?


    I am lost and can't figure this out!!!!

    Assume that the density of both mixtures are equal to the density of water
    Last edited by sergeant0844; Dec 20th 2017 at 02:05 PM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Nov 2013
    From
    California
    Posts
    6,240
    Thanks
    2664

    Re: Calculate a third mixture from blending two different mixtures

    1 kg of water is 1 liter or 1000 ml

    so we have $2500 ml$ of 10% mixture

    and unlimited supply of 1% mixture

    as is this problem either works or it doesn't, let's see.

    You need $9000ml$ as the final amount so you must add $9000ml-2500ml=6500ml$ of the 1% mixture to the 10% mixture.

    This results in

    $6500ml(0.01) + 2500ml(0.1) = 65ml+250ml = 315 ml$ of salt

    This results in a $\dfrac{315ml}{9000ml} = 0.035 = 3.5\%$ solution

    are you supposed to be able to vary the amount of 10% solution as well?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor

    Joined
    Apr 2005
    Posts
    19,924
    Thanks
    3097

    Re: Calculate a third mixture from blending two different mixtures

    You want 9000 mL that is 3.33% salt so you want 9000(0.033)= 299.7 grams of salt. If you use X mL of the 1% solution and Y =mL of the 10% solution that will contain 0.01X+ 0.10Y grams of salt.

    In order that you have 9000 mL of solution you must have X+ Y= 9000. In order that you have 299.7 grams of salt, you must have 0.01X+ 0.10Y= 299.7. Solve those two equations for X and Y.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Mixtures
    Posted in the Pre-Calculus Forum
    Replies: 6
    Last Post: Mar 30th 2016, 01:52 PM
  2. Mixtures Problem
    Posted in the Algebra Forum
    Replies: 6
    Last Post: Feb 4th 2013, 07:56 PM
  3. Mixtures
    Posted in the Differential Equations Forum
    Replies: 3
    Last Post: Jan 30th 2011, 05:01 PM
  4. Mixtures
    Posted in the Algebra Forum
    Replies: 1
    Last Post: Apr 23rd 2008, 04:28 PM
  5. Percentage and blending
    Posted in the Algebra Forum
    Replies: 3
    Last Post: Apr 2nd 2008, 12:13 AM

Search Tags


/mathhelpforum @mathhelpforum