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Thread: n

  1. #1
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    n

    I apologize for the title. This is my first post. If there is a way to change it, I can't find it.

    Solve for n

    $S_n=n(\frac {a_1+a_n}{2})$
    Last edited by jschoeppler; Dec 18th 2017 at 01:57 PM.
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  2. #2
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    Re: n

    fyi, using tex tags results in ...

    $\displaystyle \dfrac{3}{4}$

    using dollar sign delimiters works ok ...

    \$\dfrac{3}{4}\$ results in ...

    $\dfrac{3}{4}$
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  3. #3
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    Re: n

    thank you! sorry, this is my first post.
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  4. #4
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    Re: n

    How were you able to type that code without it actually showing up as the fraction?
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  5. #5
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    Re: n

    Quote Originally Posted by jschoeppler View Post
    I apologize for the title. This is my first post. If there is a way to change it, I can't find it.
    Solve for n
    $S_n=n(\frac {a_1+a_n}{2})$
    $ \begin{align*}S_n&=n\left(\dfrac{a_1+a_n}{2}\right ) \\2S_n&=n(a_1+a)\\n&=\dfrac{2S_n}{(a_1+a_n)} \end{align*}$
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  6. #6
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    Re: n

    You used to be able to post math formulas here using "[ math ]" and "[ /math ]". Now, apparently, you have to use "$" and "$" to set apart Latex.

    $\displaystyle \sqrt{\frac{a}{b}}$

    $\sqrt{\frac{a}{b}}$
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