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Thread: Word Problem I got sort of right I think

  1. #1
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    Post Word Problem I got sort of right I think

    Two squares are such that the sum of their areas are 11m^2 and the difference of their area are 7m^2. Find the length of a side of each square.

    this is what i attempted and i think it's sort of right

    ( A * B ) + ( A * B ) = 11m^2

    ( A * B ) - ( A * B ) = 7m^2

    2a + 2b = sqrt 11 = 3.316

    2a - 2b = sqrt 7 = 2.645
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  2. #2
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    Re: Word Problem I got sort of right I think

    Two squares are such that the sum of their areas are 11m^2 and the difference of their area are 7m^2.
    $a^2+b^2=11$

    $a^2-b^2=7$

    --------------------

    $2a^2=18$

    finish it ...
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  3. #3
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    Re: Word Problem I got sort of right I think

    a^2 = 18 / 2

    a ^ 2 = 9

    sqrt a = 3
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    Re: Word Problem I got sort of right I think

    Quote Originally Posted by diehardmath4 View Post
    a^2 = 18 / 2

    a ^ 2 = 9

    sqrt a = 3
    $a=3$, not $\sqrt{a} = 3$

    what about $b$?
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  5. #5
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    Re: Word Problem I got sort of right I think

    sub in a = 3 into equation #2

    a^2 - b^2 = 7

    a = 3

    3 - b^2 = 7

    b^2 = 7 - 3

    b^2 = 4

    sqrt b = sqrt 4

    b = 2
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  6. #6
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    Re: Word Problem I got sort of right I think

    $3^2+b^2=11$

    ... try again
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