Determine wether f(x) = 3x + 8 and g(x) = x - 8 / 3 are inverse functions.
For f(x) = 3x - 19, find the inverse f-¹(x). Minus sign is supposed to be uppercase..
Thanks, skeeter! Sorry, I'm kind of new to this.. but I'm kind of stuck with proving g[f(x)]=x. The first one should be the following, right?
1. Determine wether f(x) = 3x + 8 and g(x) = x - 8 / 3 are inverse functions.
f[g(x)] = f[(x - 8) / 3]
= 3x [(x - 8) / 3] + 8
= x - 8 + 8
= 8
g[f(x)] = g(3x + 8)
..and then how would you continue? Or would you've done it differently?
2. I understood this one.. should be the following?
f^-1(x) = (x + 19) / 3
Br,
Evan