I don't know where i'm going wrong on this question ( question # 8 )

$3x^2 - 7x + 2 = 0$

$a=3,~b=-7,~c=2$

$r_1,r_2 = \dfrac{7\pm \sqrt{(-7)^2 - (4)(3)(2)}}{(2)(3)}$

$r_1,r_2 = \dfrac{7 \pm \sqrt{49 - 24}}{6}$

$r_1,r_2 = \dfrac{7 \pm \sqrt{25}}{6}$

$r_1,r_2 =\dfrac{7\pm 5}{6}$

$r_1,r_2 = \dfrac{12}{6},~\dfrac{2}{6}$

$r_1,r_2 = 2,~\dfrac 1 3$

You appear to have done that. The odd thing is that you seem to have $\displaystyle \sqrt{25}= 5\sqrt{5}$ which is, of course, wrong.