ok I hate logs so how would I simplify: z= 3- 3 log(x+y) thank you
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Originally Posted by hrm ok I hate logs so how would I simplify: z= 3- 3 log(x+y) one "simplifies" an expression or "solves" an equation. you've posted an equation ... what are you solving for?
$z=3 \big(1-\log (x+y)\big)=3\log\left( \dfrac{e}{x+y}\right) $ Which one do you think is "simpler"?
Last edited by SlipEternal; Sep 16th 2017 at 07:14 AM.
solving for z
sorry guys I posted the question wrong! log z = 3 - 3log(x+y)
$z=\left(\dfrac{e}{x+y}\right)^3$
Originally Posted by hrm sorry guys I posted the question wrong! log z = 3 - 3log(x+y) $z = e^{3-3\log(x+y)} = \dfrac{e^3}{e^{\log(x+y)^3}} = \left(\dfrac{e}{x+y}\right)^3$
thank you so much!
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