8xy = 2x + 21y
3xy^{2}= 2x + 15y
I want to find the x and y
Answers :
x= 3
y = 2
Multiply the first equation by 5: 40xy= 10x+ 105y
Multiply the second equation by 7: 21xy^2= 14x+ 105y
Subtract: 40xy- 21xy^2= -4x
If x is not 0, divide by x: 40y- 21y^2= -4 or 21y^2- 40y- 4= 0. Solve that using the quadratic formula for y, then solve for x. That gives x= 3, y= 2 and another solution.
If x is 0 then y= 0. x= y= 0 is a third solution.