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Thread: solving this equation

  1. #1
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    Lightbulb solving this equation

    Hi All,

    I am trying to solve this:

    y^(2)=3x-5x+12, find the value of Y?

    Please help me understand it.

    Thanks
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  2. #2
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    Re: solving this equation

    Quote Originally Posted by rwahdan View Post
    Hi All,
    I am trying to solve this:
    y^(2)=3x-5x+12, find the value of Y?
    What you have written is $y^2=\large 3x-5x+12$. I don't think you meant that
    Do you mean $y^2=\large 3x^2-5x+12~?$
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  3. #3
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    Re: solving this equation

    If you really meant y^2= 3x^2- 5x+ 12 then you "undo" the square with the square root: y= \pm\sqrt{3x^2- 5x+12}.

    There is no "Y", as opposed to "y" in what you have. Did you mean "y"?
    Last edited by HallsofIvy; Jun 19th 2017 at 03:13 PM.
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  4. #4
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    Re: solving this equation

    Quote Originally Posted by rwahdan View Post
    I am trying to solve this:

    y^(2)=3x-5x+12, find the value of Y?

    Please help me understand it.
    First, I will assume that when you say "find the value of Y" you really mean "find the value of y".
    In mathematics, the exactness and precision of statements are absolutely essential. Y and y are not the same!

    Second, you say "I am trying to solve this".
    But it is only equations that can be solved. What you have written is not an equation, as such.
    It is a statement, telling us about the mathematical relationship that exists between two unknowns, x and y.
    Hence there is nothing to solve.
    However, if you had another equation containing x and y then you would have a pair of simultaneous equations, which, theoretically, could be solved for x and y.

    Third, as your mathematical statement stands, the only sensible thing that one can be asked to do with it is to rearrange it so that it reads "y = something not containing y".
    And that is provided in post #3, above.

    I hope all of that helps.

    Al.
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  5. #5
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    Re: solving this equation

    Actually, y^2= 3x- 5x+ 12 is an equation! It has "=" and everything.
    Thanks from SlipEternal
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