1. solving this equation

Hi All,

I am trying to solve this:

y^(2)=3x-5x+12, find the value of Y?

Thanks

2. Re: solving this equation

Originally Posted by rwahdan
Hi All,
I am trying to solve this:
y^(2)=3x-5x+12, find the value of Y?
What you have written is $y^2=\large 3x-5x+12$. I don't think you meant that
Do you mean $y^2=\large 3x^2-5x+12~?$

3. Re: solving this equation

If you really meant $y^2= 3x^2- 5x+ 12$ then you "undo" the square with the square root: $y= \pm\sqrt{3x^2- 5x+12}$.

There is no "Y", as opposed to "y" in what you have. Did you mean "y"?

4. Re: solving this equation

Originally Posted by rwahdan
I am trying to solve this:

y^(2)=3x-5x+12, find the value of Y?

First, I will assume that when you say "find the value of Y" you really mean "find the value of y".
In mathematics, the exactness and precision of statements are absolutely essential. Y and y are not the same!

Second, you say "I am trying to solve this".
But it is only equations that can be solved. What you have written is not an equation, as such.
It is a statement, telling us about the mathematical relationship that exists between two unknowns, x and y.
Hence there is nothing to solve.
However, if you had another equation containing x and y then you would have a pair of simultaneous equations, which, theoretically, could be solved for x and y.

Third, as your mathematical statement stands, the only sensible thing that one can be asked to do with it is to rearrange it so that it reads "y = something not containing y".
And that is provided in post #3, above.

I hope all of that helps.

Al.

5. Re: solving this equation

Actually, $y^2= 3x- 5x+ 12$ is an equation! It has "=" and everything.