P = a1 + a4 + a7 + a10..... + a34
Q = a2 + a5 + a8 + a11 .... + a35
how many terms in each one?
The answer is 12
* i came to conclusion that the q for each one is q^{3}
It is certainly true that both 1, 4, 7, ..., 34, and 2, 5, 8, ..., 35 are arithmetic sequences with common difference 3 so, since 34= 1+ 3(11), and 35= 2+ 3(11), each has 11+ 1= 12 terms. I have no idea what "the $\displaystyle q$ for each one is $\displaystyle q^3$" means.