This is the problem:
$\displaystyle (x + 3)(3x - 4)$
My math teacher taught us this:
F - first
O - outside
I - inside
L - last
So would I go something like this?
$\displaystyle (x * 3x) + (3 * 3x) + (x * - 4) + (3 * 4)$
I'm really confused.
This is the problem:
$\displaystyle (x + 3)(3x - 4)$
My math teacher taught us this:
F - first
O - outside
I - inside
L - last
So would I go something like this?
$\displaystyle (x * 3x) + (3 * 3x) + (x * - 4) + (3 * 4)$
I'm really confused.
no. the red 4 should be -4. you got it (except you did FIOL instead of FOIL )
just multiply out and simplify
you do know that "first" means "the first terms in each bracket" and analogous meanings for the others?
anyway, what FOIL basically boils down to, is taking each term in one set of brackets and multiplying every term in the other set
you are correct
you could have also realized that this was the form of the difference of two squares and get the answer in one step (if you don't know what "the difference of two squares" is referring to, forget about it, you will soon enough. it seems that practicing FOIL is your objective, and it will always work for multiplying two binomials)