Reduce to Lowest Terms:

$\displaystyle \frac {x^3+8y^3}{x^2+2xy}$

This is what I got (probably not right):

$\displaystyle \frac {x^2-2xy+4y^2}{x}$

Printable View

- Feb 5th 2008, 01:38 PMPandaPandaReducing to Lowest Terms
Reduce to Lowest Terms:

$\displaystyle \frac {x^3+8y^3}{x^2+2xy}$

This is what I got (probably not right):

$\displaystyle \frac {x^2-2xy+4y^2}{x}$ - Feb 5th 2008, 01:43 PMHenderson
Looks good. Nice job.