I am having difficulty with converting nested sigma notations into closed forms.
sum [from i=3 to n] (i * sum [from j=i+1 to n] (3) )
I apologize for the notation but I hope I portrayed the question.
The inner one I thought that it would be i(n- (i+1) +1)3 = 3i(n-i) {which I thought is the closed form for a constant} then substitute into the outer one.
Any help or explanation muchly appreciated.
Ray
The inner summation is multiplied by i. Do I multiply it through before I calculate the outer? So therefore 3n sum(i^2) - 3 sum(i^3)? Then used the closed forms for ^2 and ^3 respectively?
Thanks for what you have given so far and once again I apologize for notation.