It says to use the Factor Theorem, but I can't think of how to approach it using the Factor Theorem.

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- February 4th 2008, 03:06 PMJeavusHow do I factor (a^7-b^7)?
It says to use the Factor Theorem, but I can't think of how to approach it using the Factor Theorem.

- February 4th 2008, 03:08 PMbobak
well if you have a = b then you have found a zero of the function. so a-b must be a factor.

- February 4th 2008, 03:10 PMJeavus
Alright, I knew that already.

How does the long division turn out? - February 4th 2008, 03:14 PMJeavus
Nevermind...

(a-b)(a^6+a^5*b+a^4*b^2+a^3*b^3+a^2*b^4+a*b^5+b^6) - February 4th 2008, 03:18 PMbobak
it ugly, synthetic division may be easier.

but what you have here is know as a binomial number that might make it a it easier.