1. ## Square Root Equality

The problem is to solve for x:

OK. It seems simple enough. I said 31 is the answer.
Isn't it true that:

The answer is "no real number solutions".

Why?

2. ## Re: Square Root Equality

It is true that $\displaystyle (6)^2=36$ and $\displaystyle (-6)^2 = 36$

BUT

$\displaystyle \sqrt {36} =6$ and $\displaystyle -\sqrt{36} = -6$.

The $\displaystyle \sqrt{}$ sign represents the positive square root.

The $\displaystyle -\sqrt{}$ sign represents the negative square root.

In other words, $\displaystyle \sqrt{anything}$ will never be negative.