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Thread: Train Question

  1. #1
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    Train Question

    A freight train is 27 minutes late when it makes its usual trip between Town Aand Town B at an average speed of 56 km/h. For another trip between Town Aand Town B, the freight train is 42 minutes late when its average speed is54 km/h. What is the distance between Town A and Town B?

    Is there an algebraic way to solve this
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  2. #2
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    Re: Train Question

    27 min = 9/20 hr

    42 min = 7/10 hr

    let $t$ = normal amount of time in hrs to not be late

    $d$ = distance in km between towns

    $d = 56\left(t+\dfrac{9}{20}\right)$

    $d = 54\left(t+\dfrac{7}{10}\right)$

    solve the system of equations for $t$, then determine $d$
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  3. #3
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    Re: Train Question

    t is 63/10 and d is 378?
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  4. #4
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    Re: Train Question

    Quote Originally Posted by Ilikebugs View Post
    t is 63/10 and d is 378?
    substitute your solution for $t$ in each equation and see if you get the same value of $d$
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  5. #5
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    Re: Train Question

    I got 378 for both
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