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Thread: Equation

  1. #1
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    Equation

    How do I put z = x/ (x + y) in terms of x?
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  2. #2
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    Re: Equation

    It's a simple problem dude!

    Rewrite it as proportion

    $\dfrac{z}{1}=\dfrac{x}{x+y}\\ \text{Now, apply cross multiplication} \\ x=z(x+y) \\ x=xz+yz \\ x-xz=yz \\ x(1-z)=yz\\ x=\dfrac{yz}{(1-z)}\tag*{}$
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  3. #3
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    Re: Equation

    $z = \dfrac{x}{x+y}$

    $(x+y)z = x$

    $x z + y z = x$

    $y z = x-xz$

    $y z = x(1-z)$

    if $z\neq 1$ then $x = \dfrac{y z}{1-z}$

    if $z=1$ then $y=0$ and $x$ can equal anything other than 0.
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