In the xy-plane, the graph of y =2x2 −15x intersects the graph of y=x atthe points (0, 0) and (a, a) . What is the value of ‘a’ ? D Do I factor out first? Thanks
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$2x^2 - 15x = x$ solve for x
Originally Posted by allo95 In the xy-plane, the graph of y =2x2 −15x intersects the graph of y=x atthe points (0, 0) and (a, a) . What is the value of ‘a’ ? D Do I factor out first? Thanks Actually I'd write it slightly different: We know that (x, y) = (a, a) for some value of a. So becomes -Dan
Thanks for replies. However, still not sure how to solve it.
$2a^2 - 15a = a$ $2a^2 - 16a = 0$ $2a(a-8) = 0$ so, what is the non-zero value of $a$?
8! Thanks!!!