2st/s2 − t2+1/s+t − 4/s−t
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Do you mean s^2 and t^2 instead of s2 and t2 ? Do you understand that s/s^2 = 1/s ?
Here is the problem:
Originally Posted by cwall 2st/(s^2 − t^2) + 1/(s + t) − 4/(s − t) in future, use parentheses to group terms and carets (^) to indicate exponents ... common denominator is $s^2-t^2 = (s+t)(s-t)$ ... $\dfrac{2st}{s^2-t^2} + \dfrac{s-t}{s^2-t^2} - \dfrac{4(s+t)}{s^2-t^2}$ ... take it from here?
I'm getting answer of (2st + 5s + 3t) / (s^2 - t ^ 2). Is that accurate?
Originally Posted by cwall I'm getting answer of (2st + 5s + 3t) / (s^2 - t ^ 2). Is that accurate? $\dfrac{2st+(s-t)-4(s+t)}{s^2-t^2}$ try again ...
Example: -a(b + c) = -ab - ac Hokay?