this is what i did next i dont know if it is right or not.
(-cb over ab - ca over ba) x + b^2 over ab + a^2 over ba + 2ab = 0 so there is a common denominator then crossed all the common denominators out. So its..
(-cb - ca)x + b^2 + a^2 + 2ab = 0 i then moved the x part over to the other side so its...
b^2 + a^2 + 2ab = 0 over ac + bc then i moved the rest of equation over to the other side so it is now...
b^2 + a^2 + 2ab over ac + bc is this the correct answer? i am really confused because the book had the answer as x = a^2 + b^2 + 2ab over ac + bc = a+b over c. Is the book right or am i? also can some one show me how to actually show up as a over b instead of typing it
thanks in advance
the book is right, it hard to read through your work though because of how you typed it, so i will show you the solution.
so we were at:
............bring the x term on the other side, we are solving for x after all
.............combine all the fractions
.........divide both sides by (ac + bc)/ab
.............the ab's cancel, now factorize the other terms
use LaTex, learn how to herealso can some one show me how to actually show up as a over b instead of typing it
or simply type a/b to mean a over b. but please, use parentheses if you have a lot of terms. that is, type (ac - ab)/(b + c) to mean