Hey hopefully some one can help me with this cuase i cant get it for the life of me
solve for 'x'
b-cx over a + a -cx over b + 2 = 0
also im new so i dont know how to get all signs and stuff lol
Thanks for the help.
$\displaystyle \frac {b - cx}a + \frac {a - cx}b + 2 = 0$ ..........split up the fractions
$\displaystyle \Rightarrow \frac ba - \frac {cx}a + \frac ab - \frac {cx}b + 2 = 0$ .............group like terms and factor out the x
$\displaystyle \Rightarrow \left( - \frac ca - \frac cb \right)x + \frac ba + \frac ab + 2 = 0$
can you continue?
i have not come to help the math geniuses, but to help sinners do his problem... ...did anyone but me get that?
this is what i did next i dont know if it is right or not.
(-cb over ab - ca over ba) x + b^2 over ab + a^2 over ba + 2ab = 0 so there is a common denominator then crossed all the common denominators out. So its..
(-cb - ca)x + b^2 + a^2 + 2ab = 0 i then moved the x part over to the other side so its...
b^2 + a^2 + 2ab = 0 over ac + bc then i moved the rest of equation over to the other side so it is now...
b^2 + a^2 + 2ab over ac + bc is this the correct answer? i am really confused because the book had the answer as x = a^2 + b^2 + 2ab over ac + bc = a+b over c. Is the book right or am i? also can some one show me how to actually show up as a over b instead of typing it
thanks in advance
the book is right, it hard to read through your work though because of how you typed it, so i will show you the solution.
so we were at:
$\displaystyle \left( - \frac ca - \frac cb \right)x + \frac ba + \frac ab + 2 = 0$ ............bring the x term on the other side, we are solving for x after all
$\displaystyle \Rightarrow \left( \frac ca + \frac cb \right)x = \frac ba + \frac ab + 2$ .............combine all the fractions
$\displaystyle \Rightarrow \left( \frac {ac + bc}{ab}\right)x = \frac {a^2 + b^2 + 2ab}{ab}$ .........divide both sides by (ac + bc)/ab
$\displaystyle \Rightarrow x = \frac {a^2 + b^2 + 2ab}{ab} \cdot \frac {ab}{ac + bc}$ .............the ab's cancel, now factorize the other terms
$\displaystyle \Rightarrow x = \frac {(a + b)^2}{ab} \cdot \frac {ab}{c(a + b)}$
$\displaystyle \Rightarrow x = \frac {(a + b)^2}{c(a + b)} $
$\displaystyle \Rightarrow x = \frac {a + b}{c}$
use LaTex, learn how to herealso can some one show me how to actually show up as a over b instead of typing it
or simply type a/b to mean a over b. but please, use parentheses if you have a lot of terms. that is, type (ac - ab)/(b + c) to mean $\displaystyle \frac {ac - ab}{b + c}$