under the condition 2x²+y²=4 for real numbers x, y, the maximum value of 4x + y² is.....and the minimum one is .....
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I thought... y² = 4 - 2x² 4x + y² = 4x + 4 - 2x²..... maximum is (1,6), but the minimum? I thought
by derivate i get the maximum point but and the minimum?
Last edited by provasanteriores; Jan 6th 2017 at 11:21 AM.
note that $2x^2+y^2 = 4$ is an ellipse with $-\sqrt{2} \le x \le \sqrt{2}$ and $-2 \le y \le 2$ the value of $4x+y^2$ will be a minimum when $x = -\sqrt{2}$ and $y=0$
thanks!!!