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Thread: Partial Fractions

  1. #1
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    Partial Fractions

    Hi, Im really stuck with resolving this problem into partial fractions. Please help!!!!

    x^2-x-13
    (x^2+7)(x-2)
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  2. #2
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    Re: Partial Fractions

    Quote Originally Posted by sw200383 View Post
    Hi, Im really stuck with resolving this problem into partial fractions. Please help!!!!
    x^2-x-13
    (x^2+7)(x-2)
    It is not difficult. See HERE
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  3. #3
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    Re: Partial Fractions

    $\dfrac{x^2-x-13}{(x-2)(x^2+7)} = \dfrac{A}{x-2} + \dfrac{Bx+C}{x^2+7}$

    $x^2-x-13 = A(x^2+7) + (Bx+C)(x-2)$

    $x^2-x-13 = Ax^2+7A + Bx^2+Cx-2Bx-2C$

    $x^2-x-13 = (A+B)x^2+(C-2B)x + (7A-2C)$

    match coefficients ...

    $A+B=1$

    $C-2B = -1$

    $7A-2C = -13$

    solve the system for $A$, $B$, and $C$ ...
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