# Thread: Partial Fractions

1. ## Partial Fractions

Hi, Im really stuck with resolving this problem into partial fractions. Please help!!!!

x^2-x-13
(x^2+7)(x-2)

2. ## Re: Partial Fractions

Originally Posted by sw200383
Hi, Im really stuck with resolving this problem into partial fractions. Please help!!!!
x^2-x-13
(x^2+7)(x-2)
It is not difficult. See HERE

3. ## Re: Partial Fractions

$\dfrac{x^2-x-13}{(x-2)(x^2+7)} = \dfrac{A}{x-2} + \dfrac{Bx+C}{x^2+7}$

$x^2-x-13 = A(x^2+7) + (Bx+C)(x-2)$

$x^2-x-13 = Ax^2+7A + Bx^2+Cx-2Bx-2C$

$x^2-x-13 = (A+B)x^2+(C-2B)x + (7A-2C)$

match coefficients ...

$A+B=1$

$C-2B = -1$

$7A-2C = -13$

solve the system for $A$, $B$, and $C$ ...