Originally Posted by

**CODEONE** *A plane flying the 3458-mi trip from New York City to London has a 50-mph tailwind. The flight's point of no return is the point at which the flight time required to return to New York is the same as the time required to continue to London. If the speed of the plane in still air is 360 mph, how far is New York from the point of no return?*

Can anyone lead me in the right direction with this one? I've been at it for an hour and am brain dead x.x
the 50-mph tail wind means the plane's speed to London is

mph and the plane's speed to New York is

mph

let

be the distance from New York to the point of no return

then

is the distance from London to the point of no return.

let

be the time to fly to London from the point of no return

let

be the time to fly to New York from the point of no return

recall that:

so,

and

since the times from the point of no return are the same, we have:

now solve for

Hey i don't usually sign up for forums but i did to message you. I am doing this same problem for my intermediate algebra class, the problem here is probably from the same book in section 8.4, number 31, on pg.586 (Introdoctury and intermediate Algebra by Marvin L. Bittinger, Judith A. Beecher.)

**CODEONE**. Because this math problem is an odd number, they post all the odd answers in the back of the book. My math teacher only assigns us odd problems so we can always double check our answers so we know were using right methods. Anyways i'll get righ to it, the answer for this particular problem according to my test (this is the exact same problem from the text) is "1489mi". I don't know how to come to this answer. After re-reading the problem the answer does make since (seeing as the speed of the plane increases going and decreases on returning). Your explanation for setting up the equation seems plausable but in solving it i get a completely weird answer. I come to 10719.8???? Am i doing something wrong, cuz this problem is killing me, did u make a mistake, please respond!