X is not equal to Y

(x/y)+x = (y/x)+y

What is the value of (1/x) + (1/y)

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- Apr 24th 2006, 03:57 PM #1

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- Apr 24th 2006, 05:23 PM #2

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Originally Posted by**Slipknotfanatic89**

Thus,

$\displaystyle \frac{x}{y}+x=\frac{y}{x}+y$

Thus,

$\displaystyle \frac{x}{y}-\frac{y}{x}=y-x$

Thus,

$\displaystyle \frac{x^2-y^2}{xy}=y-x$

Thus,

$\displaystyle \frac{(x+y)(x-y)}{xy}=y-x$

Thus, since $\displaystyle y-x\not =0$

$\displaystyle \frac{x+y}{xy}=-1$

Thus, (express fraction as),

$\displaystyle \frac{1}{x}+\frac{1}{y}=-1$

- Apr 24th 2006, 06:03 PM #3

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- Apr 24th 2006, 06:09 PM #4

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