Help me solve the square root of a square root.

**coopsterdude** · April 24th 2006, 07:41 AM

Here's an image of my problem.

**earboth** · April 24th 2006, 08:03 AM

Originally Posted by coopsterdude

Here's an image of my problem.

Hello,

there are a few different ways to simplify this term:

$\sqrt{12 \cdot \sqrt{3}}=\sqrt{ \sqrt{12^2 \cdot3}}= \sqrt[4]{432}$

or:

$\sqrt{12 \cdot \sqrt{3}}=\sqrt{2^2 \cdot 3 \cdot \sqrt{\cdot3}}= 2 \cdot \sqrt{\sqrt{3^2 \cdot 3}}=2 \cdot \sqrt[4]{27}$

Greetings

EB

**rgep** · April 29th 2006, 01:13 AM

... or $\sqrt{12\sqrt{3}} = (12(3^{1/2}))^{1/2} = (12)^{1/2}((3)^{1/2})^{1/2}$ = $(2^2.3)^{1/2} 3^{1/4} = (2^2)^{1/2} 3^{1/2+1/4} = 2.3^{3/4} = 2\sqrt[4]{27}$ .

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