There is a limited range of
over which this can have a solution. For
instance the inequality cannot hold if
. So plug in
in
turn for
and then solve for
. Keep any solutions for which
is
equal to the assumed value used.
As an example we will work the case where we assume
.
Then we want solutions of:
which is a quadratic in
, so using the quadratic formula:
,
which is complex and so not an admissible solution (I will assume we want
real solutions).
Now lets try assuming
, then:
and so
are solutions of this equation and
is consistent with
our assumption and so is a solution of the original problem.
Carrying on like this you will find all of the remaining solutions.
RonL