Ok, so i would get $\displaystyle (x+5)(x+1)over(x+5)(x-5)$
Do i just leave it like that?
No, now you have the problem in a form where you have a common x + 5 in the numerator and denominator. NOW divide. But remember that you can't divide by 0, so at the end you must write the line $\displaystyle x \neq -5$.