Five friends met for lunch, and they all shook hands. Each person shook the other persons right hand only once. What was the total number of handshakes?
Would you add 5+5?
Printable View
Five friends met for lunch, and they all shook hands. Each person shook the other persons right hand only once. What was the total number of handshakes?
Would you add 5+5?
No. Let A B C D E be the people. Then A shakes hands with B,C,D,E. Then B shakes hands with C,D,E but not A because they already shook hands. Then C shakes hands with D,E. And D shakes hands with only E.Quote:
Originally Posted by eh501
How would you know when to do that, when to multiply or when to add?
Each problem is different, you need to understand how to approach a problem and decide whether you have to add or multiply.Quote:
Originally Posted by eh501
You can also do it another way. Draw a picture and the lines represent the people who shook hands. Then count the number of lines.
Ok, so whats the answer?
You are going to find the answer. I basically gave you the solution.Quote:
Originally Posted by eh501
I know you did but i really don't know what to do..do i just add up the letters? I still came up with 10.
Yes, 10 is the right answer. If you add up the lines. But your reasoning that 5+5=10 is wrong. Try for example 4 people instead of 5. Then the answer would be 3+2+1 = 6 and not 4 + 4 = 8.Quote:
Originally Posted by eh501
If n people shake hands with each other such each pair of persons shake hands once and only once, the total number of handshakes is.