# Thread: What is the EASIEST way to solve this?

1. ## What is the EASIEST way to solve this?

Just what the title says, is there a really easy way to get to the solution for this problem

Pasting this screen pic on this assessment won't cut it.

2. Originally Posted by Ranger SVO
Just what the title says, is there a really easy way to get to the solution for this problem

Pasting this screen pic on this assessment won't cut it.
Hello,

I don't know if I can show you the easiest way, but with "my way" you get the solution. Maybe this is sufficient(?):

$\displaystyle \frac{2^x + 3}{2^{x-1}}=2.000092$ . Expand the nominator to $\displaystyle \frac{1}{2} \cdot 2^x$ and then multiply both sides by the nominator:

$\displaystyle 2^x + 3=2.000092 \cdot \frac{1}{2} \cdot 2^x$

$\displaystyle 2^x + 3=1.000046 \cdot 2^x$. Now subtract $\displaystyle 2^x$ on both sides of this equation:

$\displaystyle 3=0.000046 \cdot 2^x$. After dividing by the coefficint of $\displaystyle 2^x$ you'll get:

$\displaystyle 65217.3913 = 2^x$. That means:

$\displaystyle x \approx \log_{2}{65217.3913}$

$\displaystyle x \approx \frac{\ln{65217.3913}}{\ln{2}} \approx 15.99296911$

Greetings

EB

3. Thats exactly what I was looking for. I kept forgetting to simpyfy the fraction first. ( So I have a new rule: remove denominator whenever possible)

Thank you

4. earboth: I'm curious and not trying to pick on you or anything...

Is the term "nominator" a legitimate term for "numerator"? I've never heard of it before.

-Dan

5. Originally Posted by topsquark
earboth: I'm curious and not trying to pick on you or anything...
Is the term "nominator" a legitimate term for "numerator"? I've never heard of it before.
-Dan
Hello,

of course you are curious - but that's what I am too, otherwise I wouldn't have registered to this forum.

1. You maybe have noticed that I am not a native speaker of English.

2. The denominator is called in german "Nenner" what means literally translated "namer". I changed this "namer" into a more Latin form and came up with a brand new word.

Greetings

EB

6. Originally Posted by earboth
Hello,

of course you are curious - but that's what I am too, otherwise I wouldn't have registered to this forum.

1. You maybe have noticed that I am not a native speaker of English.

2. The denominator is called in german "Nenner" what means literally translated "namer". I changed this "namer" into a more Latin form and came up with a brand new word.

Greetings

EB
Actually, no, I hadn't noticed you aren't a "native" English speaker. Your English is quite good! Anyway, "nominator" is a better guess than anything I'd've come up with. My problem is generally the reverse...German was the main language of Physics when Quantum Mechanics was born, so many of the terms I have to remember are derived from German, of which I only know the word "nein" (which probably isn't even spelled correctly!) (And thank Heavens that the Japanese have backed off in Particle Physics since the 90s. I can deal with having to learn German, but I've heard Japanese is almost as hard to learn as English! )

-Dan