Hello,
I'm studying for my exam right now and I just cannot recall how to do one radicals question.

16-sqrt320 / 8
so that's what I do remember:
16 - 4sqrt20 / 8
However I cannot think of any way to continue, I'm pretty sure that it has nothing to do with conjugate?
Thanks,

2. Originally Posted by Universe
Hello,
I'm studying for my exam right now and I just cannot recall how to do one radicals question.

16-sqrt320 / 8
so that's what I do remember:
16 - 4sqrt20 / 8
However I cannot think of any way to continue, I'm pretty sure that it has nothing to do with conjugate?
Thanks,
first off, use parentheses to clarify your question. is it $16 - \frac {\sqrt{320}}8$ ?

secondly, what are we supposed to be doing here? simplifying??

3. (16-4sqrt20) / 8 This is the question
And yes it is simplifying.
Thanks,

4. Originally Posted by Universe
(16-4sqrt20) / 8 This is the question
And yes it is simplifying.
Thanks,
okay. so first note that $\sqrt{20} = 2 \sqrt{5}$ (do you know how i got that?)

so: $\frac {16 - 4 \sqrt{20}}8 = \frac {16 - 8 \sqrt{5}}8 = \frac {16}8 - \frac {8 \sqrt{5}}8 = 2 - \sqrt{5}$

This is my 64th post!!!!!

5. Yea I got it.
Thanks for the help.