Results 1 to 3 of 3

Math Help - need a little help

  1. #1
    Newbie
    Joined
    Apr 2006
    Posts
    3

    need a little help

    sinplify

    4 line under the 4 and a nine under the line. [ 3 a line under then 7 - 1 line under then 7 ]
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,830
    Thanks
    123
    Quote Originally Posted by eloge1174
    sinplify

    4 line under the 4 and a nine under the line. [ 3 a line under then 7 - 1 line under then 7 ]
    Hello,

    I'm just guessing:
    Do you mean: \frac{4}{9} \cdot \frac{3}{7-1}=?

    If so you'll get: \frac{4}{9} \cdot \frac{3}{6}=?

    \frac{4}{9} \cdot \frac{1}{2}=\frac{2}{9}

    Maybe I guessed right.

    Greetings

    EB
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,830
    Thanks
    123
    Quote Originally Posted by bounine
    the {4}{9} is right but the rest is supposed to be {3}{7} - {1}{7}
    Hello,

    now I get you:

    \frac{4}{9} \cdot \frac{3}{7} - \frac{1}{7}=

    Do first the product:

    \frac{12}{63} - \frac{1}{7}=\frac{4}{21} - \frac{1}{7}

    The common nominator is 21. So you get:

    \frac{4}{21} - \frac{3}{21}=\frac{1}{21}

    Greetings

    EB
    Follow Math Help Forum on Facebook and Google+


/mathhelpforum @mathhelpforum