sinplify

4 line under the 4 and a nine under the line. [ 3 a line under then 7 - 1 line under then 7 ]

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- Apr 22nd 2006, 05:39 PMeloge1174need a little help
sinplify

4 line under the 4 and a nine under the line. [ 3 a line under then 7 - 1 line under then 7 ] - Apr 22nd 2006, 09:57 PMearbothQuote:

Originally Posted by**eloge1174**

I'm just guessing:

Do you mean: $\displaystyle \frac{4}{9} \cdot \frac{3}{7-1}=?$

If so you'll get: $\displaystyle \frac{4}{9} \cdot \frac{3}{6}=?$

$\displaystyle \frac{4}{9} \cdot \frac{1}{2}=\frac{2}{9}$

Maybe I guessed right.

Greetings

EB - Apr 22nd 2006, 10:19 PMearbothQuote:

Originally Posted by**bounine**

now I get you:

$\displaystyle \frac{4}{9} \cdot \frac{3}{7} - \frac{1}{7}=$

Do first the product:

$\displaystyle \frac{12}{63} - \frac{1}{7}=\frac{4}{21} - \frac{1}{7}$

The common nominator is 21. So you get:

$\displaystyle \frac{4}{21} - \frac{3}{21}=\frac{1}{21}$

Greetings

EB