Ok, I am graphing P=(1,2) with slope m=3. This is how I worked out

$\displaystyle y-2=3(x-1)$

=$\displaystyle y-2=3x-3$

=$\displaystyle y=3x-3+2$

=$\displaystyle y=3x-1$

If x=0 then;

$\displaystyle y=3(0)-1$

=$\displaystyle y=-1$

and so (0,-1)

this would be my second point no, or is this my run? In checking with the book's answer to see if I had done this right it showed my second point to be (2,5) with a run of 1 and a rise of 3......Did I do something wrong in the calculations!?

Thanks!!