a train travelling at 30m/s is at a certain instant 1500m from the station. what is the value of uniform deceleration required for the train to come to a stop at the station HELP
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Use v=u+at and s=(u+v)t/2 Since the final velocity v is 0 you get 30=-at and 1500=30t/2 You can get t from the second equation and the first equation tells you that a=-30/t
Originally Posted by a tutor Use v=u+at and s=(u+v)t/2 Since the final velocity v is 0 you get 30=-at and 1500=30t/2 You can get t from the second equation and the first equation tells you that a=-30/t :s :S :s umm im not great on maths what does that mean HELPPPP LOL haha
Are you not familiar with v=u+at and s=(u+v)t/2 ? May I ask... What course are you studying? How's your algebra? Anyway I'll finish this problem for you but I won't make a habit of it. 1500=30t/2 3000=30t t=3000/30 t=100 30=-at a=-30/t a=-30/100 a=-0.3
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