# Math Help - e^...

1. ## e^...

f(x)= e^(3x+1) -2
the curve y=f(x) meets the y-axis at the point P and the x-axis at the point Q
find the exact coordinates of P and Q
ive tried to work out P and Q by taking x=0 and y=0 respectively is this right? it just doesnt seem like much working out for the amount of marks it's worth. can someone please show me their working for this question?

2. $x=0\Rightarrow y=e-2\Rightarrow P(0,e-2)$
$y=0\Rightarrow e^{3x+1}=2\Rightarrow 3x+1=\ln 2\Rightarrow\displaystyle x=\frac{\ln 2-1}{3}\Rightarrow Q\left(\frac{ln 2-1}{3},0\right)$

3. Originally Posted by red_dog
$x=0\Rightarrow y=e-2\Rightarrow P(0,e-2)$
$y=0\Rightarrow e^{3x+1}=2\Rightarrow 3x+1=\ln 2\Rightarrow\displaystyle x=\frac{\ln 2-1}{3}\Rightarrow Q\left(\frac{ln 2-1}{3},0\right)$
oh, i did get it right! ok thanks...makes me feel better to have it confirmed!