solve 3(2h+1)-2(h-4)=21 how do i do this? i factorise it: 6h+3-2h-8=21 now wot do i do? u dont have to tell me the answer but could u please tell me wot the next step is?
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Originally Posted by help_me solve 3(2h+1)-2(h-4)=21 how do i do this? i factorise it: 6h+3-2h-8=21 now wot do i do? u dont have to tell me the answer but could u please tell me wot the next step is? collect all the h's on one side and all the numbers on the other so... 6h-2h=21-3+8 4h=26 can you do it from here?
Originally Posted by Oranges&Lemons collect all the h's on one side and all the numbers on the other so... 6h-2h=21-3+8 4h=26 can you do it from here? 4h=26 so h is 6.5? thanks alot
Originally Posted by help_me solve 3(2h+1)-2(h-4)=21 how do i do this? i factorise it: 6h+3-2h-8=21 now wot do i do? u dont have to tell me the answer but could u please tell me wot the next step is? Hello, unfortunately you made a small but very effective mistake. If you expand the brackets the 2nd line should read: $\displaystyle 6h+3-2h+8=21$ Collect like terms: $\displaystyle 4h +11 =21$ and after a few steps you'll get $\displaystyle h = \frac52$
Originally Posted by earboth Hello, unfortunately you made a small but very effective mistake. If you expand the brackets the 2nd line should read: $\displaystyle 6h+3-2h+8=21$ Collect like terms: $\displaystyle 4h +11 =21$ and after a few steps you'll get $\displaystyle h = \frac52$ oh yeah, my bad. i didnt even think to check if what you had written in the first place was right or not, sorry!
dats alrite thanks for pointing it out and o and l dats alrite every1 makes mistakes! lol
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