1. ## solving algebra

solve 3(2h+1)-2(h-4)=21

how do i do this?

i factorise it:
6h+3-2h-8=21
now wot do i do?
u dont have to tell me the answer but could u please tell me wot the next step is?

2. Originally Posted by help_me
solve 3(2h+1)-2(h-4)=21

how do i do this?

i factorise it:
6h+3-2h-8=21
now wot do i do?
u dont have to tell me the answer but could u please tell me wot the next step is?

collect all the h's on one side and all the numbers on the other so...
6h-2h=21-3+8
4h=26
can you do it from here?

3. Originally Posted by Oranges&Lemons
collect all the h's on one side and all the numbers on the other so...
6h-2h=21-3+8
4h=26
can you do it from here?
4h=26
so h is 6.5?
thanks alot

4. Originally Posted by help_me
solve 3(2h+1)-2(h-4)=21

how do i do this?

i factorise it:
6h+3-2h-8=21
now wot do i do?
u dont have to tell me the answer but could u please tell me wot the next step is?
Hello,

unfortunately you made a small but very effective mistake.
If you expand the brackets the 2nd line should read:

$\displaystyle 6h+3-2h+8=21$

Collect like terms:

$\displaystyle 4h +11 =21$

and after a few steps you'll get $\displaystyle h = \frac52$

5. Originally Posted by earboth
Hello,

unfortunately you made a small but very effective mistake.
If you expand the brackets the 2nd line should read:

$\displaystyle 6h+3-2h+8=21$

Collect like terms:

$\displaystyle 4h +11 =21$

and after a few steps you'll get $\displaystyle h = \frac52$
oh yeah, my bad. i didnt even think to check if what you had written in the first place was right or not, sorry!

6. ## oh

dats alrite thanks for pointing it out and o and l dats alrite every1 makes mistakes! lol