Originally Posted by

**Morzilla** I know how to factor this $\displaystyle t^2-16=0$ $\displaystyle (t-4)(t+4)$ but today I am asked to find the real solutions for equations that are quadratic in form....

$\displaystyle t^4-16$....?!

This is how I worked it out, for some reason I think (know) I did something wrong...

$\displaystyle t^4-16=0$

= $\displaystyle (t^2-4)(t^2+4)$

= $\displaystyle (t-2)(t+2)(t+2)(t+2)$

Now should this be the answer $\displaystyle (t-2)(t+2)(t+2)(t+2)$ or should it be this {-2,2}. By solving this I *might* be able to solve this one $\displaystyle x^4-5x^2+4=0$

Thanks once again guys!!