The three cube roots of 3-4i are located on a circle with radius , the real cube root of the absolute value of 3-4i, at three equal arcs. So each arc is measured at . So let then one root is
What are the other two?
well my teacher got 5 as the radius which i get and 306.87 degrees as the angle theta (might be mispelled). but then he goes from there to 5^(1/3)e^(306.87 degrees*i) sorry if this is cluttered. then he put that in polar form. but somewhere along the road he did the angle theta + 360/ 3 which got 222.3 degrees. from there i guess he got the other 2 roots. but im just a little confused in the methods used here. Sorry to ask but can you break it down into a step by step process, if possible? sorry i should be using latex for this stuff.