Thread: Problem in Differentiation

Find the coordinates of the turning points on the curve y^3 + 3xy^2 – x^3 = 3.

How can I find turning points by this equation? Please help me.

Originally Posted by geton

Find the coordinates of the turning points on the curve y^3 + 3xy^2 – x^3 = 3.

How can I find turning points by this equation? Please help me.

A 'turning point" of a function can be determined by where the relative maxima and relative minima are.

So take your first derivative, set it equal to 0, and solve for x.

-Dan