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Thread: Triangle

  1. #1
    Junior Member
    Joined
    Oct 2007
    Posts
    68

    Triangle

    If the area of a triangle is $\displaystyle x^3+x^2-4x-4$ and the height is $\displaystyle 2x+2$, find the base in terms of $\displaystyle x$

    Given choices

    A$\displaystyle x^2-4$

    B$\displaystyle 2x^2-8$

    C$\displaystyle \frac{x^2-4}{2}$

    D$\displaystyle x^2-2$
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  2. #2
    Senior Member
    Joined
    Dec 2007
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    Melbourne
    Posts
    428
    A = 0.5bh

    A = x^3+x^2-4x-4
    h = 2x+2.

    Now you can solve for b
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