If the area of a triangle is $\displaystyle x^3+x^2-4x-4$ and the height is $\displaystyle 2x+2$, find the base in terms of $\displaystyle x$

Given choices

A$\displaystyle x^2-4$

B$\displaystyle 2x^2-8$

C$\displaystyle \frac{x^2-4}{2}$

D$\displaystyle x^2-2$