This shouldn't be hard, but I can't ever seem to remember what to do with a problem like so:

c^2 + 12 = 7c and it asks me to solve it. Do I square root both sides? Or what?

same goes for ones like:

(y+4)^2 - 81 = 0

Thank you for the help.

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- Jan 16th 2008, 06:57 AMtmandersonNeed help solving.....squares..
This shouldn't be hard, but I can't ever seem to remember what to do with a problem like so:

c^2 + 12 = 7c and it asks me to solve it. Do I square root both sides? Or what?

same goes for ones like:

(y+4)^2 - 81 = 0

Thank you for the help. - Jan 16th 2008, 07:12 AMtmanderson
Alright, I managed to use the quadratic on those, though I am having trouble with one similar to this:

x^2 + 1 = 4x

Thanks for the help again. - Jan 16th 2008, 07:12 AMSean12345
The second is easier as there are less steps;

Now for the first;

We want this in the same form as above i.e.

Now compare co-effecients;

Hence

Now solve like number 2. - Jan 16th 2008, 07:15 AMSean12345