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Math Help - I need help simplifying ...

  1. #1
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    I need help simplifying ...

    Help me simplify ...

    sqrt{90(2x-3y)^6}
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  2. #2
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    Use parentheses to clarify meaning.

    Do you mean this: \sqrt{90*(2x-3y)^6}?

    Hints:

    90 = 9*10

    (2x-3y)^{6}\;=\;[(2x-3y)^{3}]^{2}

    Let's see what you get.
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  3. #3
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    Quote Originally Posted by TKHunny View Post
    Use parentheses to clarify meaning.

    Do you mean this: \sqrt{90*(2x-3y)^6}?

    Hints:

    90 = 9*10

    (2x-3y)^{6}\;=\;[(2x-3y)^{3}]^{2}

    Let's see what you get.
    Thank you. I only just joined the forums today. I've tried to get the math text functions down as best I could. The function I was trying to write appears as you have typed it. I'll take your hints and see what I can do with them.
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  4. #4
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    I'm getting (3x-4y)^3

    Is that correct? I multiplied the 90 into the equations making 180x-240y to 3x-4y
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by XIII13Thirteen View Post
    I'm getting (3x-4y)^3

    Is that correct? I multiplied the 90 into the equations making 180x-240y to 3x-4y
    Not quite. Think of it this way:
    \sqrt{90(3x - 4y)^6} = \sqrt{90} \cdot \sqrt{(3x - 4y)^6}

    What does \sqrt{90} simplify to?

    -Dan
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  6. #6
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    Quote Originally Posted by topsquark View Post
    Not quite. Think of it this way:
    \sqrt{90(3x - 4y)^6} = \sqrt{90} \cdot \sqrt{(3x - 4y)^6}

    What does \sqrt{90} simplify to?

    -Dan
    3\sqrt{10}
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  7. #7
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    So is it

    3\sqrt{10} * [(2x-3y)^{3}]^{2} ?
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  8. #8
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by XIII13Thirteen View Post
    So is it

    3\sqrt{10} * [(2x-3y)^{3}]^{2} ?
    Well, you forgot about your other square root.
    3\sqrt{10} \cdot (2x - 3y)^3

    -Dan
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  9. #9
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    3\sqrt{10} \cdot \sqrt{[(2x - 3y)^3]^2}

    OK . Thank you. I've been away from pre-cal for some time and I'm a bit rusty on factorization. I appreciate all of your help
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