Help me simplify ...

$\displaystyle sqrt{90(2x-3y)^6}$

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- Jan 15th 2008, 07:56 AMXIII13ThirteenI need help simplifying ...
Help me simplify ...

$\displaystyle sqrt{90(2x-3y)^6}$ - Jan 15th 2008, 08:22 AMTKHunny
Use parentheses to clarify meaning.

Do you mean this: $\displaystyle \sqrt{90*(2x-3y)^6}$?

Hints:

90 = 9*10

$\displaystyle (2x-3y)^{6}\;=\;[(2x-3y)^{3}]^{2}$

Let's see what you get. - Jan 15th 2008, 09:12 AMXIII13Thirteen
- Jan 15th 2008, 09:17 AMXIII13Thirteen
I'm getting $\displaystyle (3x-4y)^3$

Is that correct? I multiplied the 90 into the equations making 180x-240y to 3x-4y - Jan 15th 2008, 09:31 AMtopsquark
- Jan 15th 2008, 02:19 PMXIII13Thirteen
- Jan 15th 2008, 05:58 PMXIII13Thirteen
So is it

$\displaystyle 3\sqrt{10} * [(2x-3y)^{3}]^{2}$ ? - Jan 15th 2008, 08:37 PMtopsquark
- Jan 16th 2008, 05:37 AMXIII13Thirteen
$\displaystyle 3\sqrt{10} \cdot \sqrt{[(2x - 3y)^3]^2}$

OK :). Thank you. I've been away from pre-cal for some time and I'm a bit rusty on factorization. I appreciate all of your help