Results 1 to 7 of 7

Math Help - help

  1. #1
    Newbie
    Joined
    Jan 2008
    Posts
    2

    help

    I need help with a math question There are 7 kids in a family ages ranging from 6-16 there is one set of twins the mean is 11, the mediam is 10 and the mode is 15 I need to find the ages of the chidren also the set of twins
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member
    Joined
    Jan 2008
    From
    UK
    Posts
    484
    Thanks
    65
    Draw seven dashes _ _ _ _ _ _ _

    Fill in the median.

    Put in the 6 and the 16

    Since the mode is 15 you can fill two more spaces.

    Ask yourself...what's the total of all the ages?

    What's the total of the other two ages?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member
    Joined
    Jan 2008
    From
    UK
    Posts
    484
    Thanks
    65
    In reply to your other thread.

    Did you manage to calculate the total?

    remember mean = total / number of numbers

    m = t / n

    Can you rearrange this to get t?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Newbie
    Joined
    Jan 2008
    Posts
    2

    I am just not getting it

    I am just not getting it. I feel real dumb. Can you maybe so me an example of another word promblem. Thank you.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    GAMMA Mathematics
    colby2152's Avatar
    Joined
    Nov 2007
    From
    Alexandria, VA
    Posts
    1,172
    Awards
    1
    Quote Originally Posted by rhess View Post
    I need help with a math question There are 7 kids in a family ages ranging from 6-16 there is one set of twins the mean is 11, the mediam is 10 and the mode is 15 I need to find the ages of the chidren also the set of twins
    Ages: 6, x, x, 10, 15, 15, 16

    Sum of those five ages is 62, mean is 11, so the total sum of ages must be 77. The sum of the two x's, the unknown ages must be 15, and the two ages are not equal, so they must be 7 and 8 to preserve the mode of 15.
    Last edited by colby2152; January 14th 2008 at 09:24 AM.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by colby2152 View Post
    Ages: 6, x, x, 10, 15, 15, 16

    Sum of those five ages is 62, mean is 11, so the total sum of ages must be 77. The sum of the two x's, the unknown ages must be 11, so one age must be less than 6. There is a false statement somewhere in this problem.
    77-62=15

    and as the two ages are not equal they are 7 and 8. So the ages are:

    6, 7, 8, 10, 15, 15, 16

    RonL
    Follow Math Help Forum on Facebook and Google+

  7. #7
    GAMMA Mathematics
    colby2152's Avatar
    Joined
    Nov 2007
    From
    Alexandria, VA
    Posts
    1,172
    Awards
    1
    Quote Originally Posted by CaptainBlack View Post
    77-62=15

    and as the two ages are not equal they are 7 and 8. So the ages are:

    6, 7, 8, 10, 15, 15, 16

    RonL
    Thanks for pointing that out!
    Follow Math Help Forum on Facebook and Google+


/mathhelpforum @mathhelpforum