1. ## help

I need help with a math question There are 7 kids in a family ages ranging from 6-16 there is one set of twins the mean is 11, the mediam is 10 and the mode is 15 I need to find the ages of the chidren also the set of twins

2. Draw seven dashes _ _ _ _ _ _ _

Fill in the median.

Put in the 6 and the 16

Since the mode is 15 you can fill two more spaces.

Ask yourself...what's the total of all the ages?

What's the total of the other two ages?

Did you manage to calculate the total?

remember mean = total / number of numbers

m = t / n

Can you rearrange this to get t?

4. ## I am just not getting it

I am just not getting it. I feel real dumb. Can you maybe so me an example of another word promblem. Thank you.

5. Originally Posted by rhess
I need help with a math question There are 7 kids in a family ages ranging from 6-16 there is one set of twins the mean is 11, the mediam is 10 and the mode is 15 I need to find the ages of the chidren also the set of twins
Ages: 6, x, x, 10, 15, 15, 16

Sum of those five ages is 62, mean is 11, so the total sum of ages must be 77. The sum of the two x's, the unknown ages must be 15, and the two ages are not equal, so they must be 7 and 8 to preserve the mode of 15.

6. Originally Posted by colby2152
Ages: 6, x, x, 10, 15, 15, 16

Sum of those five ages is 62, mean is 11, so the total sum of ages must be 77. The sum of the two x's, the unknown ages must be 11, so one age must be less than 6. There is a false statement somewhere in this problem.
77-62=15

and as the two ages are not equal they are 7 and 8. So the ages are:

6, 7, 8, 10, 15, 15, 16

RonL

7. Originally Posted by CaptainBlack
77-62=15

and as the two ages are not equal they are 7 and 8. So the ages are:

6, 7, 8, 10, 15, 15, 16

RonL
Thanks for pointing that out!