im terrible at factoring..please help?
(4x+1)^2 - (16x^2 + 4x)
i treated it as a difference of squares
so i did:
(4x+1 + 16x^2+4x)(4x+1 - 16x^2 - 4x)
which i further simplified to:
(16x^2 +8x+1)(-16x^2 +1)
and im pretty sure this isnt right.
im terrible at factoring..please help?
(4x+1)^2 - (16x^2 + 4x)
i treated it as a difference of squares
so i did:
(4x+1 + 16x^2+4x)(4x+1 - 16x^2 - 4x)
which i further simplified to:
(16x^2 +8x+1)(-16x^2 +1)
and im pretty sure this isnt right.
Hello, checkmarks!
Factor the second term: .$\displaystyle (4x+1)^2 - 4x(4x + 1)$Factor: .$\displaystyle (4x+1)^2 - (16x^2 + 4x)$
i treated it as a difference of squares . . . . $\displaystyle {\color{blue}(16x^2 + 4x)}$ is not a square
Take out the common factor: .$\displaystyle (4x+1)\bigg[(4x+1) - 4x\bigg] $
And we have: .$\displaystyle (4x + 1)[4x + 1 - 4x) \;\;=\;\;(4x+1)(1) \;\;=\;\;\boxed{4x + 1}$