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Math Help - one factoring question

  1. #1
    Junior Member
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    Dec 2006
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    one factoring question

    im terrible at factoring..please help?

    (4x+1)^2 - (16x^2 + 4x)

    i treated it as a difference of squares
    so i did:
    (4x+1 + 16x^2+4x)(4x+1 - 16x^2 - 4x)
    which i further simplified to:
    (16x^2 +8x+1)(-16x^2 +1)

    and im pretty sure this isnt right.
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  2. #2
    Super Member

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    Lexington, MA (USA)
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    Hello, checkmarks!

    Factor: . (4x+1)^2 - (16x^2 + 4x)

    i treated it as a difference of squares . . . . {\color{blue}(16x^2 + 4x)} is not a square
    Factor the second term: . (4x+1)^2 - 4x(4x + 1)

    Take out the common factor: . (4x+1)\bigg[(4x+1) - 4x\bigg]

    And we have: . (4x + 1)[4x + 1 - 4x) \;\;=\;\;(4x+1)(1) \;\;=\;\;\boxed{4x + 1}

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