1. Help with standard form(s)?

I am completely unsure on how to go about taking points from a line and putting them into standard form.

If I have points (3, 0) and (0, -4) how would I put that into a standard form? I know that the standard form will have x and y on the same side, but it seems the steps on doing so are what confuse me.

If anyone could please explain the process of putting the points listed above into standard form I would highly appreciate it.

2. Originally Posted by tmanderson
I am completely unsure on how to go about taking points from a line and putting them into standard form.

If I have points (3, 0) and (0, -4) how would I put that into a standard form? I know that the standard form will have x and y on the same side, but it seems the steps on doing so are what confuse me.

If anyone could please explain the process of putting the points listed above into standard form I would highly appreciate it.

I'm not exactly sure what you want. Do you want the equation of a line?

If so then $\displaystyle m = \frac{delta \ y}{delta \ x}$

$\displaystyle m = \frac{0 - (-4)}{3 - 0}$

$\displaystyle y = \frac{4}{3} x + c$

$\displaystyle 0 = \frac{4}{3} (3) + c$

$\displaystyle c = -4$

Therefore

$\displaystyle y = \frac{4}{3} x - 4$

3. Well, the answer for this certain problem happened to be:

4x - 3y = 12

and I really don't know the steps in order to get to this point. How do you assign the 4 to the x, the 3 to the y, and 12 as the answer?

4. Originally Posted by tmanderson
Well, the answer for this certain problem happened to be:

4x - 3y = 12

and I really don't know the steps in order to get to this point. How do you assign the 4 to the x, the 3 to the y, and 12 as the answer?
The answer 4x - 3y = 12 is equivalent to the one given by janvdl, namely

$\displaystyle y = \frac{4}{3} x - 4$.

What happens when you multiply both sides of $\displaystyle y = \frac{4}{3} x - 4$ by 3 and do a little bit of re-arranging ....?

5. Ah, I got it.

It just took the answer and then simplified it to integers only.

Thank you for the help and pointers.